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400=400-16t^2
We move all terms to the left:
400-(400-16t^2)=0
We get rid of parentheses
16t^2-400+400=0
We add all the numbers together, and all the variables
16t^2=0
a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$t=\frac{-b}{2a}=\frac{0}{32}=0$
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